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// image file $file = dirname(__FILE__)."/Chrysanthemum.jpg"; $curl = curl_init(); curl_setopt_array($curl, array( CURLOPT_URL => 'http://www.pixhost.org/cover-upload/', CURLOPT_RETURNTRANSFER => true, CURLOPT_REFERER =>...

as Apathetic said post your complete code here, what have you tried? what did not work? there is no detail except a post array. Help us to help you, give us the detail that matters about what's going on.

Call to SOCA or nearly located Police station, I am sure they will help you to sort it out (jk) and joke aside, why do you wants to start a warez site? there are already more then enough, start something better.

Hello, send me details of your project. Thanks

If you recently broke up dont listen sad songs, it will just make your situation worse. Make yourself busy with other stuff, Join Gym, put your effort and anger on building muscles, here is a video to motivate you, watch it carefully... http://www.youtube.com/watch?v=MzpWT66Km8E another look at...

Billion Dollars Love in 2012? now only love is money, If you have money, you have love and everything besides you.

what kind of help you required? any code to show? there are many javascript coders around so your best option is to post what kind of issue you have. cheers

Thank you for kind words and nice doing business with you. replied via pm. replied via pm. Best Regards.

give your div an id and use padding. HTML: <div id="social"> <a href="#"><img src="http://givingcancerthefinger.com/wp-content/plugins/social-sharing-toolkit/images/icons_medium/twitter.png" alt="picture of a pumpkin" /></a> <a href="#"><img...

http://www.craftysyntax.com/ Free and good.

I am hosting with him from several months and he is one of the best host/guy around. good luck

And please dont post your php info like this in public, it can cause you damage.

if you are using smarty (as u mentioned above) see answer here: http://goo.gl/uViQG

if you wants to display html from a file and not execte php code from that file then you can use fopen, here is a small example. $file = "location/file.php"; $f = fopen($file, "r"); while ( $line = fgets($f, 1000) ) { print $line; } and if you wants to display php with...

you can ignore that error with @ ( some text's encoding is not being recognized by iconv) $message = @iconv("UTF-8","Windows-1252//IGNORE",$message);

try this $message = iconv("UTF-8","Windows-1252//IGNORE",$message); are you scraping turkish characters?

congrats Blaze, well deserved...

I am back and available for new projects, if someone require my service please send me full detail of your project via pm. Thank you for reading. Best Regards mRAza

t3od0r for isset : Returns TRUE if var exists and has value other than NULL, FALSE otherwise. so basically isset is already checking for NULL values but if you still wants to check for null use is_null ... if(isset($images[0]) && !is_null($images[0])) ... or just use if($images[0]) it will...

you can simply assign a default image i.e $image and check as below: $image = "http://link/to/Your_default_image.jpg"; if(isset($images[0])) $image = $images[0]; $variable = ''; if($images[0]) its checking if there is any image here then change $image value to that else keep your default...